Optimal. Leaf size=191 \[ -\frac{c^2 \left (16 a^2 d^2+b c (5 b c-16 a d)\right ) \tanh ^{-1}\left (\frac{\sqrt{d} x}{\sqrt{c+d x^2}}\right )}{128 d^{7/2}}+\frac{x^3 \sqrt{c+d x^2} \left (16 a^2 d^2+b c (5 b c-16 a d)\right )}{64 d^2}+\frac{c x \sqrt{c+d x^2} \left (16 a^2 d^2+b c (5 b c-16 a d)\right )}{128 d^3}-\frac{b x^3 \left (c+d x^2\right )^{3/2} (5 b c-16 a d)}{48 d^2}+\frac{b^2 x^5 \left (c+d x^2\right )^{3/2}}{8 d} \]
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Rubi [A] time = 0.186079, antiderivative size = 188, normalized size of antiderivative = 0.98, number of steps used = 6, number of rules used = 6, integrand size = 24, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.25, Rules used = {464, 459, 279, 321, 217, 206} \[ -\frac{c^2 \left (16 a^2 d^2+b c (5 b c-16 a d)\right ) \tanh ^{-1}\left (\frac{\sqrt{d} x}{\sqrt{c+d x^2}}\right )}{128 d^{7/2}}+\frac{1}{64} x^3 \sqrt{c+d x^2} \left (16 a^2+\frac{b c (5 b c-16 a d)}{d^2}\right )+\frac{c x \sqrt{c+d x^2} \left (16 a^2 d^2+b c (5 b c-16 a d)\right )}{128 d^3}-\frac{b x^3 \left (c+d x^2\right )^{3/2} (5 b c-16 a d)}{48 d^2}+\frac{b^2 x^5 \left (c+d x^2\right )^{3/2}}{8 d} \]
Antiderivative was successfully verified.
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Rule 464
Rule 459
Rule 279
Rule 321
Rule 217
Rule 206
Rubi steps
\begin{align*} \int x^2 \left (a+b x^2\right )^2 \sqrt{c+d x^2} \, dx &=\frac{b^2 x^5 \left (c+d x^2\right )^{3/2}}{8 d}+\frac{\int x^2 \sqrt{c+d x^2} \left (8 a^2 d-b (5 b c-16 a d) x^2\right ) \, dx}{8 d}\\ &=-\frac{b (5 b c-16 a d) x^3 \left (c+d x^2\right )^{3/2}}{48 d^2}+\frac{b^2 x^5 \left (c+d x^2\right )^{3/2}}{8 d}+\frac{1}{16} \left (16 a^2+\frac{b c (5 b c-16 a d)}{d^2}\right ) \int x^2 \sqrt{c+d x^2} \, dx\\ &=\frac{1}{64} \left (16 a^2+\frac{b c (5 b c-16 a d)}{d^2}\right ) x^3 \sqrt{c+d x^2}-\frac{b (5 b c-16 a d) x^3 \left (c+d x^2\right )^{3/2}}{48 d^2}+\frac{b^2 x^5 \left (c+d x^2\right )^{3/2}}{8 d}+\frac{1}{64} \left (c \left (16 a^2+\frac{b c (5 b c-16 a d)}{d^2}\right )\right ) \int \frac{x^2}{\sqrt{c+d x^2}} \, dx\\ &=\frac{c \left (16 a^2+\frac{b c (5 b c-16 a d)}{d^2}\right ) x \sqrt{c+d x^2}}{128 d}+\frac{1}{64} \left (16 a^2+\frac{b c (5 b c-16 a d)}{d^2}\right ) x^3 \sqrt{c+d x^2}-\frac{b (5 b c-16 a d) x^3 \left (c+d x^2\right )^{3/2}}{48 d^2}+\frac{b^2 x^5 \left (c+d x^2\right )^{3/2}}{8 d}-\frac{\left (c^2 \left (16 a^2+\frac{b c (5 b c-16 a d)}{d^2}\right )\right ) \int \frac{1}{\sqrt{c+d x^2}} \, dx}{128 d}\\ &=\frac{c \left (16 a^2+\frac{b c (5 b c-16 a d)}{d^2}\right ) x \sqrt{c+d x^2}}{128 d}+\frac{1}{64} \left (16 a^2+\frac{b c (5 b c-16 a d)}{d^2}\right ) x^3 \sqrt{c+d x^2}-\frac{b (5 b c-16 a d) x^3 \left (c+d x^2\right )^{3/2}}{48 d^2}+\frac{b^2 x^5 \left (c+d x^2\right )^{3/2}}{8 d}-\frac{\left (c^2 \left (16 a^2+\frac{b c (5 b c-16 a d)}{d^2}\right )\right ) \operatorname{Subst}\left (\int \frac{1}{1-d x^2} \, dx,x,\frac{x}{\sqrt{c+d x^2}}\right )}{128 d}\\ &=\frac{c \left (16 a^2+\frac{b c (5 b c-16 a d)}{d^2}\right ) x \sqrt{c+d x^2}}{128 d}+\frac{1}{64} \left (16 a^2+\frac{b c (5 b c-16 a d)}{d^2}\right ) x^3 \sqrt{c+d x^2}-\frac{b (5 b c-16 a d) x^3 \left (c+d x^2\right )^{3/2}}{48 d^2}+\frac{b^2 x^5 \left (c+d x^2\right )^{3/2}}{8 d}-\frac{c^2 \left (16 a^2+\frac{b c (5 b c-16 a d)}{d^2}\right ) \tanh ^{-1}\left (\frac{\sqrt{d} x}{\sqrt{c+d x^2}}\right )}{128 d^{3/2}}\\ \end{align*}
Mathematica [A] time = 0.101858, size = 157, normalized size = 0.82 \[ \frac{\sqrt{d} x \sqrt{c+d x^2} \left (48 a^2 d^2 \left (c+2 d x^2\right )+16 a b d \left (-3 c^2+2 c d x^2+8 d^2 x^4\right )+b^2 \left (-10 c^2 d x^2+15 c^3+8 c d^2 x^4+48 d^3 x^6\right )\right )-3 c^2 \left (16 a^2 d^2-16 a b c d+5 b^2 c^2\right ) \log \left (\sqrt{d} \sqrt{c+d x^2}+d x\right )}{384 d^{7/2}} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.011, size = 259, normalized size = 1.4 \begin{align*}{\frac{{b}^{2}{x}^{5}}{8\,d} \left ( d{x}^{2}+c \right ) ^{{\frac{3}{2}}}}-{\frac{5\,{b}^{2}c{x}^{3}}{48\,{d}^{2}} \left ( d{x}^{2}+c \right ) ^{{\frac{3}{2}}}}+{\frac{5\,{b}^{2}{c}^{2}x}{64\,{d}^{3}} \left ( d{x}^{2}+c \right ) ^{{\frac{3}{2}}}}-{\frac{5\,{b}^{2}{c}^{3}x}{128\,{d}^{3}}\sqrt{d{x}^{2}+c}}-{\frac{5\,{b}^{2}{c}^{4}}{128}\ln \left ( x\sqrt{d}+\sqrt{d{x}^{2}+c} \right ){d}^{-{\frac{7}{2}}}}+{\frac{ab{x}^{3}}{3\,d} \left ( d{x}^{2}+c \right ) ^{{\frac{3}{2}}}}-{\frac{abcx}{4\,{d}^{2}} \left ( d{x}^{2}+c \right ) ^{{\frac{3}{2}}}}+{\frac{ab{c}^{2}x}{8\,{d}^{2}}\sqrt{d{x}^{2}+c}}+{\frac{ab{c}^{3}}{8}\ln \left ( x\sqrt{d}+\sqrt{d{x}^{2}+c} \right ){d}^{-{\frac{5}{2}}}}+{\frac{{a}^{2}x}{4\,d} \left ( d{x}^{2}+c \right ) ^{{\frac{3}{2}}}}-{\frac{{a}^{2}cx}{8\,d}\sqrt{d{x}^{2}+c}}-{\frac{{a}^{2}{c}^{2}}{8}\ln \left ( x\sqrt{d}+\sqrt{d{x}^{2}+c} \right ){d}^{-{\frac{3}{2}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.93364, size = 767, normalized size = 4.02 \begin{align*} \left [\frac{3 \,{\left (5 \, b^{2} c^{4} - 16 \, a b c^{3} d + 16 \, a^{2} c^{2} d^{2}\right )} \sqrt{d} \log \left (-2 \, d x^{2} + 2 \, \sqrt{d x^{2} + c} \sqrt{d} x - c\right ) + 2 \,{\left (48 \, b^{2} d^{4} x^{7} + 8 \,{\left (b^{2} c d^{3} + 16 \, a b d^{4}\right )} x^{5} - 2 \,{\left (5 \, b^{2} c^{2} d^{2} - 16 \, a b c d^{3} - 48 \, a^{2} d^{4}\right )} x^{3} + 3 \,{\left (5 \, b^{2} c^{3} d - 16 \, a b c^{2} d^{2} + 16 \, a^{2} c d^{3}\right )} x\right )} \sqrt{d x^{2} + c}}{768 \, d^{4}}, \frac{3 \,{\left (5 \, b^{2} c^{4} - 16 \, a b c^{3} d + 16 \, a^{2} c^{2} d^{2}\right )} \sqrt{-d} \arctan \left (\frac{\sqrt{-d} x}{\sqrt{d x^{2} + c}}\right ) +{\left (48 \, b^{2} d^{4} x^{7} + 8 \,{\left (b^{2} c d^{3} + 16 \, a b d^{4}\right )} x^{5} - 2 \,{\left (5 \, b^{2} c^{2} d^{2} - 16 \, a b c d^{3} - 48 \, a^{2} d^{4}\right )} x^{3} + 3 \,{\left (5 \, b^{2} c^{3} d - 16 \, a b c^{2} d^{2} + 16 \, a^{2} c d^{3}\right )} x\right )} \sqrt{d x^{2} + c}}{384 \, d^{4}}\right ] \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [B] time = 16.7008, size = 411, normalized size = 2.15 \begin{align*} \frac{a^{2} c^{\frac{3}{2}} x}{8 d \sqrt{1 + \frac{d x^{2}}{c}}} + \frac{3 a^{2} \sqrt{c} x^{3}}{8 \sqrt{1 + \frac{d x^{2}}{c}}} - \frac{a^{2} c^{2} \operatorname{asinh}{\left (\frac{\sqrt{d} x}{\sqrt{c}} \right )}}{8 d^{\frac{3}{2}}} + \frac{a^{2} d x^{5}}{4 \sqrt{c} \sqrt{1 + \frac{d x^{2}}{c}}} - \frac{a b c^{\frac{5}{2}} x}{8 d^{2} \sqrt{1 + \frac{d x^{2}}{c}}} - \frac{a b c^{\frac{3}{2}} x^{3}}{24 d \sqrt{1 + \frac{d x^{2}}{c}}} + \frac{5 a b \sqrt{c} x^{5}}{12 \sqrt{1 + \frac{d x^{2}}{c}}} + \frac{a b c^{3} \operatorname{asinh}{\left (\frac{\sqrt{d} x}{\sqrt{c}} \right )}}{8 d^{\frac{5}{2}}} + \frac{a b d x^{7}}{3 \sqrt{c} \sqrt{1 + \frac{d x^{2}}{c}}} + \frac{5 b^{2} c^{\frac{7}{2}} x}{128 d^{3} \sqrt{1 + \frac{d x^{2}}{c}}} + \frac{5 b^{2} c^{\frac{5}{2}} x^{3}}{384 d^{2} \sqrt{1 + \frac{d x^{2}}{c}}} - \frac{b^{2} c^{\frac{3}{2}} x^{5}}{192 d \sqrt{1 + \frac{d x^{2}}{c}}} + \frac{7 b^{2} \sqrt{c} x^{7}}{48 \sqrt{1 + \frac{d x^{2}}{c}}} - \frac{5 b^{2} c^{4} \operatorname{asinh}{\left (\frac{\sqrt{d} x}{\sqrt{c}} \right )}}{128 d^{\frac{7}{2}}} + \frac{b^{2} d x^{9}}{8 \sqrt{c} \sqrt{1 + \frac{d x^{2}}{c}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.12663, size = 235, normalized size = 1.23 \begin{align*} \frac{1}{384} \,{\left (2 \,{\left (4 \,{\left (6 \, b^{2} x^{2} + \frac{b^{2} c d^{5} + 16 \, a b d^{6}}{d^{6}}\right )} x^{2} - \frac{5 \, b^{2} c^{2} d^{4} - 16 \, a b c d^{5} - 48 \, a^{2} d^{6}}{d^{6}}\right )} x^{2} + \frac{3 \,{\left (5 \, b^{2} c^{3} d^{3} - 16 \, a b c^{2} d^{4} + 16 \, a^{2} c d^{5}\right )}}{d^{6}}\right )} \sqrt{d x^{2} + c} x + \frac{{\left (5 \, b^{2} c^{4} - 16 \, a b c^{3} d + 16 \, a^{2} c^{2} d^{2}\right )} \log \left ({\left | -\sqrt{d} x + \sqrt{d x^{2} + c} \right |}\right )}{128 \, d^{\frac{7}{2}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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